![]() I hope this whole concept is clear to you. So therefore it is forming sigma and sigma. See it is having triple bond, that means two sigma bond, it is there one firm carbon carbon and one from this hydrogen. So therefore this carbon consists of sp three hybridization, violent case of carbon. So therefore this is sigma, sigma, sigma and sigma. We can write it as in this form hydrogen and hydrogen. That means 42 signatures there and again, this is what this is. So here for this carbon 123 sigma bond it is there So 3-σ bond that means it is sp two hybridization while in the case of CH to this carbon B, it is having four hydrogen for hydrogen. Single born consist of sigma born double bond consists of one pie and one sigma bond here while the triple bond consists of two pi and two sigma bond the pi bond doesn't take participate in the hybridization. ![]() For this carbon here the sigma bonnet, is there sigma bonnet is there? And this is one double bond consists of one sigma and one pi bond. Yesterday as you can see here for let us suppose carbon A. geraldinegudino04 is waiting for your help. geraldinegudino04 geraldinegudino04 4 days ago Biology College Drag the appropriate labels to their respective targets. See double bone ch ch two see triple bond ch and this is C. Find an answer to your question Drag the appropriate labels to their respective targets. ![]() And if there are two sigma bond then the hybridization will be sp. If there are four sigma bonds then the hybridization will be sp three and if there are three sigma bond then the hybridization will be sp two. So therefore the number of sigma bond, it will decide the hybridization. They do not participate in the hybridization and only sigma bonds will participate in hybridization. This hybridization depends on number of sigma bonds, sigma bonds and pi bonds. ![]() So firstly let us see the number of sigma bond. Carbon we need to find out the hybridization. In this question we are given a molecule that is ch teary C double bond C ch ch two. ![]()
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